Two planes are 1380 miles apart and traveling toward each other. One plane is traveling80 mph faster than the other plane. The planes pass each other in 1.5 hours. Find thespeed of each plane.

Answer: plane 1: 420 mph; plane 2: 500 mphStep-by-step explanation:This is a physics exercise, but in order to solve this problem, you need to identify both planes first:Let's call the plane 1 speed XV1 = XAnd V2 would be:V2 = V1 + 80 = X + 80If we combine both speeds:V = V1 + V2 = X + X + 80 = 2X + 80Now that we have an expression for the combined speed, let's see the rest of the data:Distance: d = 1380 mileTime: t = 1.5 hWe also know that the formula to get speed is:V = d/tWe have the combined speed, so, let replace it in the above formula to solve for X:2X + 80 = 1380/1.52X + 80 = 9202X = 920 - 802X = 840X = 840/2X = V1 = 420 mphWe have V1, so to get V2:V2 = 420 + 80 = 500 mph